Construct A Rectangle Flat With Fl 5 Cm And La 3 Cm Class 8 Ap Ts Construction of quadrilaterals# class 8# exercise 3.1 (d) ap and telangana state boards.ex 3.1 (c) ap ts state boardsconstruct a quadrilateral best with be=. 1. draw a line segment \(\overline{fl}\) with radius 5 cm. 2. with the centre f draw a ray and an arc equal to 900, 3 cm. these to meet at point t. 3. with the centres t, l draw arcs equal to 5 cm, 3 cm respectively. 4. these two arcs meet at the point ‘a’. 5. join t, a and l, a. 6. ∴ the required rectangle flat is formed.
Rectangle Flat With Fl 5 Cm La 3 Cm Sarthaks Econnect Largest Report flag outlined. answer: step by step explanation: given : a rectangle flat with fl = 5 cm and la = 3cm. solution : consider the attached figure. since opposite sides of rectangles are equal. so, fl=at=5 cm. and la=tf=3 cm. Procedure : step 1 : draw a rough sketch of the required quadrilateral and mark the given measurements. step 2 : draw Δtbe using s.a.s property of construction , by taking bt = 3.4 cm , ∠ tbe = 75° and be = 2.9 cm. step 3 : to locate the fourth vertex ‘s’ , draw an arc , with center t and radius 2.7cm (ts=2.7cm). Rectangle flat with fl = 5 cm, la = 3 cm. answer: given : in rectangle flat, fl = 5 cm. la = 3 cm. ∠fla = 90 o. procedure : step 1: draw a rough sketch of the parallelogram and mark the given measurements. here , we are given only 3 measurements. but as flat is a rectangle , we can also write that fl = at = 5 cm and la = tf = 3 cm. The given details are ab = 4.4 cm, bc = 4 cm, cd = 6.4 cm, da = 3.8 cm and bd = 6.6 cm. divide the quadrilateral into two triangles, i.e., Δabd and Δbcd. steps to construct a quadrilateral: step 1 by using sss congruency rule, draw line bd of length 6.6 cm. step 2 cut an arc with b as the centre and radius bc = 4cm.
Rectangle Flat With Fl 5 Cm La 3 Cm Sarthaks Econnect Largest Rectangle flat with fl = 5 cm, la = 3 cm. answer: given : in rectangle flat, fl = 5 cm. la = 3 cm. ∠fla = 90 o. procedure : step 1: draw a rough sketch of the parallelogram and mark the given measurements. here , we are given only 3 measurements. but as flat is a rectangle , we can also write that fl = at = 5 cm and la = tf = 3 cm. The given details are ab = 4.4 cm, bc = 4 cm, cd = 6.4 cm, da = 3.8 cm and bd = 6.6 cm. divide the quadrilateral into two triangles, i.e., Δabd and Δbcd. steps to construct a quadrilateral: step 1 by using sss congruency rule, draw line bd of length 6.6 cm. step 2 cut an arc with b as the centre and radius bc = 4cm. 6. construct a rectangle such that one side is 5 cm and one diagonal is 6.8 cm. solution: steps of construction: (i) construct ab = 5 cm. (ii) at the point a, draw ∠bap = 900. (iii) taking b as centre and 6.8 cm radius, construct an arc which meets ap at d. (iv) taking a as centre and 6.8 cm radius, construct an arc. Question. 192 construct a quadrilateral bear in which be = 6 cm, ea = 7 cm, rb = re = 5 cm and ba = 9 cm. measure its fourth side. solution. question. 193 construct a parallelogram pour in which po = 5.5 cm, ou = 7.2 cm and \(\angle o\) = 70°.
Construct The Quadrilaterals With The Given Measurements And Write 6. construct a rectangle such that one side is 5 cm and one diagonal is 6.8 cm. solution: steps of construction: (i) construct ab = 5 cm. (ii) at the point a, draw ∠bap = 900. (iii) taking b as centre and 6.8 cm radius, construct an arc which meets ap at d. (iv) taking a as centre and 6.8 cm radius, construct an arc. Question. 192 construct a quadrilateral bear in which be = 6 cm, ea = 7 cm, rb = re = 5 cm and ba = 9 cm. measure its fourth side. solution. question. 193 construct a parallelogram pour in which po = 5.5 cm, ou = 7.2 cm and \(\angle o\) = 70°.
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