4 6 Optimization Minimize Cost Of Can Youtube

4 6 Optimization Minimize Cost Of Can Youtube Ap calculus optimization problem. This video provides an example of how to find the dimensions of a right circular cylinder that will minimized production costs.site: mathispower4u.

Ex Optimization Minimize The Cost To Make A Can With A Fixed Volume This calculus 1 video explains using optimization to minimize the cost of a box with a square base. we find a cost function for a rectangular box and use di. Consider the same open top box, which is to have volume \(216\,\text{in}^3\). suppose the cost of the material for the base is \(20¢ \text{in}^2\) and the cost of the material for the sides is \(30¢ \text{in}^2\) and we are trying to minimize the cost of this box. write the cost as a function of the side lengths of the base. Stage i: develop the function. your first job is to develop a function that represents the quantity you want to optimize. it can depend on only one variable. the steps: 1. draw a picture of the physical situation. see the figure. we’ve called the radius of the cylinder r, and its height h. 2. write an equation that relates the quantity you. We conclude that the maximum area must occur when x = 25. figure 4.6.2: to maximize the area of the garden, we need to find the maximum value of the function a(x) = 100x − 2x2. then we have y = 100 − 2x = 100 − 2(25) = 50. to maximize the area of the garden, let x = 25ft and y = 50ft. the area of this garden is 1250ft2.

Optimization Minimize Cost Example 1 Youtube Stage i: develop the function. your first job is to develop a function that represents the quantity you want to optimize. it can depend on only one variable. the steps: 1. draw a picture of the physical situation. see the figure. we’ve called the radius of the cylinder r, and its height h. 2. write an equation that relates the quantity you. We conclude that the maximum area must occur when x = 25. figure 4.6.2: to maximize the area of the garden, we need to find the maximum value of the function a(x) = 100x − 2x2. then we have y = 100 − 2x = 100 − 2(25) = 50. to maximize the area of the garden, let x = 25ft and y = 50ft. the area of this garden is 1250ft2. Find the dimensions that will minimize the cost of the metal to manufacture the can. (note: 1 liter is equivalent to 1,000 cubic centimeters.) step 1.draw a can. this is a cylinder, so we label the dimensions: radius (r) and height (h). step 2.the cost of metal to manufacture the can depends on the surface area of the can. so, we want to. This calculus video explains how to solve optimization problems. it explains how to solve the fence along the river problem, how to calculate the minimum di.